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56.25+100=c^2
We move all terms to the left:
56.25+100-(c^2)=0
We add all the numbers together, and all the variables
-1c^2+156.25=0
a = -1; b = 0; c = +156.25;
Δ = b2-4ac
Δ = 02-4·(-1)·156.25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-25}{2*-1}=\frac{-25}{-2} =12+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+25}{2*-1}=\frac{25}{-2} =-12+1/2 $
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